Question

5.
According to Bernoulli's theorem
P v2
d 2
+gh = constant. The dimensional formula of
the constant is (P = pressure, d = density, h =
height, V = velocity, g
velocity, g = acceleration
due to gravity]
[EAMCET 2005 M
A) [Mºl°T
B) (MºLT°
C) [MºlT? D) (Mºtºr)​

Answer 1

Explanation:

According to Bernoulli's theorem, dp+2v2+gh= Constant. The dimensional formula of the constant is: (P is pressure, d is density, h is height, v is velocity and g is accelaration due to gravity)

Answer 2

ㅤㅤㅤㅤ"Here is Your Solution"

☟☟

$\Large\tt\pink{♡\underline{Correct}}$ $\large{\bold{\fbox{\red A}\fbox{\purple n}\fbox{\pink s }\fbox{\orange w}\fbox{\green e}\fbox{\blue R}\red ✿}}$ Is:

$\large\tt \pink{ M^{0}{L}^{2} {T}^{ - 2} }$

$\Large\bf\underline{\red{E}\green{X}\orange{P}\pink{L}\red{A}\purple{N}\orange{A}\blue{T}\red{I}\purple{O}N}$

☛Bernoulli's theorem Gives,

$\Large \tt \purple{\frac{p}{d} + \frac{v^{2} }{2} + gh = \pink{constant}}$

⇨(P/d), (v^2)/2 and gh will have same dimension as the total of these will have same dimension.

$\large{\fcolorbox{grey}{yellow}{Therefore,}}$

Dimension of $\large\bf{ \red{\frac{p}{d}}}$ is,

$\Large\tt \red{\frac{ M {L}^{ - 1} {T}^{ - 2} }{M {L}^{ - 3} {T}^{ 0} }}$ = $\large\tt \pink{ M^{0}{L}^{2} {T}^{ - 2} }$

❖ ───── $\Large{\mathfrak{\red{\underline{ \blue{\underline{\green{\underline{\purple E \orange N \pink D}}}}}}}}$ ──── ❖