Math, asked by jasmeetnanda927, 6 hours ago

5. An elevator descends into a mine shaft at the rate of 6 m/min. If descent starts from 20 m

above the ground level, How long will it take to reach -370 m?

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Answers

Answered by SaptakGhosh
0

Answer:

The velocity of elevator = 6m/min

Total distance to be covered = (370+20)=390m

Time taken = Distance/Velocity = 390/6 = 65min

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Answered by KaoJ
0

Answer:

Distance between 20 m and -370 m = 20-(-370) = 390 m

Speed = 6 m/min

Time = 390/6 = 65 min

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