5. An elevator descends into a mine shaft at the rate of 6 m/min. If descent starts from 20 m
above the ground level, How long will it take to reach -370 m?
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Answer:
The velocity of elevator = 6m/min
Total distance to be covered = (370+20)=390m
Time taken = Distance/Velocity = 390/6 = 65min
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Answered by
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Answer:
Distance between 20 m and -370 m = 20-(-370) = 390 m
Speed = 6 m/min
Time = 390/6 = 65 min
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