Math, asked by ujjwalyaduvanshi, 11 months ago

5. An express train takes 3 hours less than a passenger train for a journey of 600 km. if
the speed of the passenger train was 10 km/hr. less than that of the express train,
find the speed of both the trains.​

Answers

Answered by ayush0763
2

Answer:

Sorry but don't actually know the answer.

Answered by GulabLachman
1

The speed of the express train is 50 km/hr and the speed of the passenger train is 40 km/hr.

Let us consider the speed of the express train to be x km/hr

Given that the speed of the passenger train is 10km/hr less than that of passenger train.

So, speed of passenger train = (x-10) km/hr

Total distance to cover = 600km

Time taken by express train = 600/x hrs

Time taken by passenger train = 600/(x-10) hrs

Given that the difference in the time taken is 3 hours.

So,

600/(x-10) - 600/x = 3

⇒ (600x-600x+6000) = 3x(x-10)

⇒ 6000 = 3x²-30x

⇒ 3x²-30x-6000 = 0

⇒ x² - 10x - 2000 = 0

⇒ x² - 50x + 40x - 2000 = 0

⇒ x(x-50) + 40(x-50) = 0

⇒ (x-50)(x+40) = 0

By Zero Product Rule,

x = 40 cant be true as speed cant be negative

So, x = 50

Speed of the express train = 50 km/hr

Speed of the passenger train = 50-10 = 40 km/hr

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