Question

5. An isosceles triangle has equal sides each 13 cm and a base 24 cm in lenge
Find its height​

Answer 1

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★ Question :-

An isosceles triangle has equal sides each 13 cm and a base 24 cm in length.Find its height ?

★ To Find :-

Find its height ?

★ Solution :-

AB = AC = 13cm

BC =24 cm

Height = Altitude = AD

An Altitude Drawn From the base from vertex of an isosceles Triangle divides the base in the two equal parts.

BC = CD

In △ ADB

AB² = AD² + DB²

(13)² = AD² +(12)²

AD² = 169 - 144

AD² = √25

AD² = 5 Cm

Hence, The Height Is 5 Cm.

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Answer 2

$\huge \mathcal {Question}$

An isosceles triangle has equal sides each 13 cm and a base 24 cm in lenge

Find its height.

$\huge \colorbox{cyan}{Solution}$

Δ Abc is an is an isosceles Δ

AB=AC=13cm

BC=24

Height=Altitude=AD

An altitude draw to the base from vertex of an isosceles triangle divides the base in two equal parts

.:. BD=CD

BD=1/2 BC=12cm

In Δ ADB

${AB}^{2} = {AD}^{2} + {DB}^{2} \\ {13}^{2} = {AD}^{2} + {12}^{2} \\ {AD}^{2} = 169 - 144 \\ {AD}^{2} = 25 \\ {AD} = 5cm$

$\huge \bold {\pink{Hope \: it \: Helps \: u}}$

THANKS!! ❤