Question

5. An isosceles triangle has equal sides each 13 cm and a base 24 cm in length Find its height​

Answer 1

Answer:

$\huge \pink{ \underbrace {\overbrace{ \purple{\mathfrak{Answer}}}}}$

Height will be

$\bold{ \frac{24}{2} = 12}$

$\bold{ {13}^{2} - {12}^{2} = {height}^{2} }$

$\bold{ {height}^{2} = 169 - 194}$

$\bold{ {height}^{2} = 25}$

$\bold{height = \sqrt{25cm} }$

$\bold \pink{height = 5cm}$

Step-by-step explanation:

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Answer 2

FINAL ANSWERE:

height of isosceles Δ ABC is 5 cm

GIVEN:

isosceles triangle 2 sides = 13 cm

and

base = 24 cm

AX=$\frac{24}{2}$=12cm

FORMULA USED:

Pythagoras theorem in triangle

ΔABX

HYPOTENIUS²=PERPENDICULAR²+BASE²

H²=P²+B²

TO FIND:

height AX

SOUTION:

in ΔABX

AB²=BX²+AX²

13²=12²+AX²

169=144+AX²

AX²=169-144

AX²=25

AX=√25

AX=5 cm

height = 5 cm

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