Question

5. An object is kept at 10 cm in front of a convex
lens. Its image is formed on the screen at
15 cm from the lens. Calculate (1) the focal
length of the lens (2) the magnification
produced by the lens.​

Answer 1

Answer:

4dkdkzlslalslkdoslsxl

Answer 2

Solution:-

ATQ;

u= -10cm

v= 15cm

f= ?; magnification= ?

we know that;

1/v- 1/u = 1/f

1/f = 1/15 - (-1)/10

= 1/15 + 1/10 == (2+3)/30

= 5/30 == 1/6 = 1/f

therefore, f = 6cm

magnification = v/u = 15/-10

= -1.5

therefore, magnification = 1.5

THANKS!!!