Question

5. An object is placed at a distance of 10 cm from a convex mirror of focal length 15cm.find the position and nature of the image.​

Answer 1

Answer:

Given that

u= -10 cm

f= 15 cm

We need to find v

We know the formula

1/f = 1/v + 1/u

Therefore, 1/v= 1/f – 1/u

Substituting the known values in the above equation we get,

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Hencev=5/30 = 6 cm

v= 6cm

Nature of the image: The image is formed behind the mirror and it is virtual and erect.

Explanation:

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Answer 2

Given:

• u = -10 cm
• Focal length (f) = 15 cm

To Find:

• We need to find v?

We know the formula;

$\\ \bullet{\boxed{\sf\pink{ \dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u} }} } \\ \\ \hookrightarrow{\sf{ \dfrac{1}{v} = \dfrac{1}{f} – \dfrac{1}{u} }}$

Substituting the known values in the above equation we get,

$\\ \hookrightarrow{\sf{ \dfrac{1}{v} = \dfrac{1}{15} + \dfrac{1}{10} }} \\ \\ \hookrightarrow{\sf{ \dfrac{1}{v} = \dfrac{(2+3)}{30} }} \\ \\ \hookrightarrow{\sf{ v = \dfrac{5}{30} }} \\ \\ \hookrightarrow{\sf\purple{v = 6 \ cm }}$

Hence,

The Position of the object is 6 cm.

Nature of the image: The image is formed behind the mirror and it is virtual and erect.