Question

5. An object of mass 10 kg is
raised from the ground upto a
height of 5 min 5s. What is the
power?(g = 10m/s2)​

Answer 1

Answer:

Work done is change in potential energy of the object. Here the assumption is that the force which lifts the body, balances the weight at all times, meaning which there is no linear velocity of the object during this motion.

All the work done by the force is reflected as the increase in the stored potential energy of the object. Potential energy is defined as a difference of potential energy between two reference points and

U2 - U1 = mgh = 10 * 10 * 5 = 500 N-m

So the work done =Change in potential energy= 500 Nm.

Answer 2

Solution :

As per the given data ,

• Mass of the object(m) = 10 kg
• Height (h) = 5 m
• Time taken (t) = 5 s
• Acceleration due to gravity (g) = 10 m/s ²

First we need to find the work done by the object .

Work done to lift the object will be due to it's potential energy.

Hence ,

$\dag \boxed{\mathtt{W = PE = m g h} }$

⇒ W = mgh

⇒ W = 10 x 10 x 5

⇒ W = 500 J

The work done by the object is 500 J

Now , as per the formula ,

⇒ P = W / t

⇒ P = 500 / 5

⇒ P = 100 W

The power is 100 W .