Question

5. An object of mass 5 kg is kept at rest. A force of 20 N acts on it for 5 s. Find the distance travelled by
object in 10 s?​

Answer 1

Answer:

200m

Explanation:

Force =Mass×Acceleration

20 = 5×a

a =20/5

a =4 m/s^2

Acceleration = distance / 5^2

4 distance /25

distance =25×4

distance =100 m

distance in 10s =2×100 =200m