Question

5. An object with a mass 10 kg moves at a constant velocity
of 10 m/s. A constant force then acts for
4 seconds on the object giving it a speed of
2 m/sin opposite direction. The acceleration produced
is :-
(1) 3 m/s
12V-3 m/s2
(3) 0.3 m/s²
(4) -0.3 m/s²​

Answer 1

Answer:

(2) -3m/s^2

Explanation:

u = 10m/s

t = 4sec

v = -2m/s ( since in opposite direction)

a = $\frac{v - u}{t}$

$a = \frac{ - 2 - 10}{4} = \frac{ - 12}{4} = - 3$

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Hope it helps....!

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