Math, asked by laskarhasnahena16, 7 months ago

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A spinner is marked with numbers from 1 to 10. What is the probability of :
(a) multiple of 3
(c) not getting a multiple of 2?
(b) getting a prime number?​

Answers

Answered by bhsrni
1

Answer:

(a)3/ 10

(c)1/2

(b)2/5

Step-by-step explanation:

Explanation of (a):

the total outcomes that are possible are 10.

the number of favorable outcomes are 3 because out of the all the numbers marked ( 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ), only 3 outcomes i.e. 3, 6 and 9 are divisible by 3.

since

probability of an event = favorable outcomes/ total number of outcomes

therefore,

probability = 3/10

(c) total outcomes are 10.

the number of favorable outcomes are 5 ( 1,3,5,7, and 9 are not divisible by 2)

therefore,

probability = 5/10 = 1/2

(b)

total outcomes = 10

number of favorable outcomes: 4 ( 2,3,5 and 7 are prime)

therefore,

probability = 4/10 = 2/5

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