√5 and -√5 are two zeros of the polynomial x³+3x²-5x-15 then third zero is
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given polynomial
p(x) = x³ +3x² -5x -15
on comparison with the standard form of a cubic polynomial
We get,
a = 1
b= 3
c = -5
d = -15
given that two roots are √5 and -√5et the third root be ß
now
sum of roots = -b/a
= > √5 -√5 + ß = -3/1
=> ß = -3
so, the roots are √5, -√5 and ß.
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