Math, asked by sg177186, 11 months ago

5 and 6 home
ne pipes are in
(c) 48 days
18. Pipes A and B can fill a tank in 5 and
respectively. Pipe C can empty it in 12 h
The tank is half full. All the three pipes
operation simultaneously. After how much
will the tank will be full​

Answers

Answered by rishu6845
1

Answer:

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Attachments:
Answered by Shreya091
158

Answer:

\huge{\mathfrak{\underline{\red{AnsWer:-}}}}

____________

\textbf{\underline{\underline{Step By step explanation:}}}

________

{\bold{\underline{\underline{Given:-}}}}

❇Pipe A can fill tank in 5hrs

❇Pipe B can fill tank in 6hrs

❇Pipe C can fill tank in 12hrs

{\bold{\underline{\underline{Find:-}}}}

❇How much time tank will take to be full =?

_________⭐

\textbf{\underline{\underline{According to question :}}}

❇Part of tank fill by pipe A in one hour =1/5

❇Part of tank fill by pipe B in one hour = 1/6

❇Part of tank C fill by pipe C in one hour =1/12

Now,

Part of tank fill by all pipes =>1/5 + 1/6 + 1/12

=>\frac {17}{60}

Time taken by all pipes =>

=>\frac{1/2}{17/60}

\large\pink{\boxed{\sf Time taken =30/17hrs}}

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