5. Andrew deposited 5500 and Anamika
deposited * 4800 in a bank. If the bank pays a
simple interest of 2% per annum, then how
much more interest would Andrew get than
Anamika after a year?
Answers
Therefore she will get Rs (2400+378.3) = Rs.2778.3 on maturity.
Explanation:
Given that, Anamika deposits Rs. 2400 at 10% annual interest for 1\frac{1}{2}1
2
1
years.
1\frac{1}{2}1
2
1
years= (1\frac{1}{2} \times 12) month =18\ month(1
2
1
×12)month=18 month = 6 months+6 months+6 months.
Since the interest is calculated in every 6 month , so the the principal will be changed after 6 month.
First 6 month:
Here P= Rs. 2400, r= 10%, time = 6 month =\frac{1}{2}
2
1
year
I_1 =\frac{Prt}{100}I
1
=
100
Prt
=\frac{2400\times 10\times \frac{1}{2} }{100}=
100
2400×10×
2
1
=Rs. 120
Second 6 month,
Here P=Rs. (2400+I₁)=Rs (2400+120)=Rs. 2520 , r= 10%, time = 6 month =\frac{1}{2}
2
1
year
I_2=\frac{Prt}{100}I
2
=
100
Prt
=\frac{2520\times 10\times \frac{1}{2} }{100}=
100
2520×10×
2
1
=Rs. 126
Third month:
Here P=Rs. (2520+I₂)=Rs (2520+126)=Rs. 2646 , r= 10%, time = 6 month =\frac{1}{2}
2
1
year
I_3=\frac{Prt}{100}I
3
=
100
Prt
=\frac{2646\times 10\times \frac{1}{2} }{100}=
100
2646×10×
2
1
=Rs. 132.3
Total interest (I)=I_1+I_2+I_3(I)=I
1
+I
2
+I
3
=Rs.( 120+126+132.3)
=Rs. 378.3
Therefore she will get Rs (2400+378.3) = Rs.2778.3 on maturity.