5. Anil sells one transistor for 880 at a gain of 10% and another for 960 at a loss of 4%. Findhis overall gain and loss per cent
Answers
Answer: 2.22%
Step-by-step explanation :1 ) Selling price of first transistor
(s.p) = Rs 880
gain( g ) = 10%
Let the Cost price = c.p
c.p = ( s.p × 100)/( 100 + g )
= ( 880 × 100 )/( 100 + 10 )
= ( 880 × 100 )/110
c.p = Rs 800
2 ) Selling price of second transistor
= Rs 960
Loss ( L ) = 4%
Cost price = ( s.p × 100 )/( 100 - L )
= ( 960 × 100 )/( 100 - 4 )
= ( 960 × 100 )/96
C.P = Rs 1000
3 ) Total cost price of two transistors
= Rs 800 + Rs 1000
= Rs 1800
4 ) Total selling price of two transistors
= Rs 880 + Rs 960
= Rs 1840
5 ) Total s.p > Total c.p
Therefore , Anil gets profit .
gain = Total s.p - total c.p
= Rs 1840 - Rs 1800
= Rs 40
6 ) Gain % = ( gain × 100 )/( total c.p )
= ( 40 × 100 )/1800
= ( 20/9 )%
≈ 2.2%
Answer:
Total cost price
=
840
×
100
120
+
960
×
100
96
=
1700
Total selling price
=
840
+
960
=
1800
Total gain
=
1800
−
1700
=
100
Gain percent
=
100
×
100
1700
=
5
15
17
%