Question

5 anko ki sabse Chhoti sankhya nikaali jismein 579 se Bhag dene par Shesh 124 hai​

Answer 1

Answer:

No this is wrong answer

Right answer is

17.2711571675

Answer 2

The required number is 10,546.

Step-by-step explanation:

Consider the provided information.

The smallest 5 digit number is 10,000

Divide 10,000 with 579.

$\frac{10,000}{579}\approx17.21$

That means if we multiply 579 with 18 that will gives us the smallest 5 digit number which is completely divisible by 579.

579×18=10,422

10,422 is the smallest 5 digit number which is completely divisible by 579.

Now we want remainder 124.

So add 124 in 10,422.

10,422+124 = 10,546

Hence, the required number is 10,546.

#Learn more

Find the smallest number of 5-digit which is exactly divisible by 312

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