Question

5 appliances are used 10 hours per day in a house. Out of which 2 appliances are of 200 w and three are of 400 W. Then calculate the amount electric energy consumed in units.

Answer 1

p=200+400

=600

1W=1000kW

600W=600/1000kW

=0.6kW

t =10 hrs

E=P×t

=0.6×10

=6kWh

Answer 2

Answer:

p=200+400

=600

1W=100kW

600kW=600/1000kW

=0.6kW

T=10hrs

E=P×T

=0.6×10

=6kWh

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