Question

5% aqueous solution of kcl was found to freeze at – 0.24°c. Calculate the van't hoff factor and degree of dissociation of the solute at this concentration (kf for h2o = 1.86 k kg mol–1).

Answer 1

Answer:

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Answer 2

Answer:

AT=0-(-0.24°C) = 0.24°C 1000KfW₂

M₂

=

ATf W₁

1000x1.86x0.5

0.24×100

= 38.75gmol-¹

Theoretical molar mass of KCI =39+35.5

⇒ 74.5gmol-¹

i = Calculated mol mass Theoretical mol mass

74.5 38.75 1.92

KCI K+ + Cl¯

1 mole 0 0

1-a

α α

Total number of moles after dissociation =

1 + a 1+α

i =

i-1 = a = 1.92 - 1

⇒ 0.92

Percentage dissociation =92%