5. Arjun is twice as old as Shreya. Five years ago his age was three times
Shreya's age. Find their present ages.
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Given
Arjun is twice as old as Shreya. Five years ago his age was three times Shreya's age.
To find
Find their present ages.
Solution
Let the present age of Sherya be x then Arjun be 2x
- After five years ago
- Shreya's age = (x - 5)
- Arjun's age = (2x - 5)
➢ According to the given condition
➡ 2x - 5 = 3(x - 5)
➡ 2x - 5 = 3x - 15
➡ 15 - 5 = 3x - 2x
➡ x = 10
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