Math, asked by THEOP, 10 months ago

5. Arjun is twice as old as Shreya. Five years ago his age was three times
Shreya's age. Find their present ages.​

Answers

Answered by Anonymous
34

Given

Arjun is twice as old as Shreya. Five years ago his age was three times Shreya's age.

To find

Find their present ages.

Solution

Let the present age of Sherya be x then Arjun be 2x

  • After five years ago
  • Shreya's age = (x - 5)
  • Arjun's age = (2x - 5)

According to the given condition

➡ 2x - 5 = 3(x - 5)

➡ 2x - 5 = 3x - 15

➡ 15 - 5 = 3x - 2x

➡ x = 10

{\underline{\boxed{\bf{Present\:age\:of\:Sherya=x=10\:year}}}}

{\underline{\boxed{\bf{Present\:age\:of\:Arjun=2x=20\:year}}}}

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