5. Atom a possesses higher values of packing fraction than atom b. The relative stabilities of a and b are
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I will assume A has higher "value" of Packing fraction and not higher "absolute value". Then the answer is B.
Explanation:
Packing fraction( let us denote it as x) is defined as
x= (M-A)/A,
where M= isotopic (actual, measured) mass
A= Mass number(theoretical on the basis of masses of individual nucleons)
Whenever A>M, that means the actual mass of nucleon is less than what is the sum of masses of protons and neutrons. This "defect" is converted into energy which is responsible for keeping the nucleus stable. This energy is called Binding Energy.
Binding energy in itself doesn't provide a good measure of stability. Rather binding energy per nucleon is a better and accepted unit. It is directly proportional to x, provided x is negative.
Lighter elements ( H1, H2, H3 ) and heavier elements( A>200) have a positive value of x, thereby making them unstable and prone to be radioactive.
Hope I have answered the question
I will assume A has higher "value" of Packing fraction and not higher "absolute value". Then the answer is B.
Explanation:
Packing fraction( let us denote it as x) is defined as
x= (M-A)/A,
where M= isotopic (actual, measured) mass
A= Mass number(theoretical on the basis of masses of individual nucleons)
Whenever A>M, that means the actual mass of nucleon is less than what is the sum of masses of protons and neutrons. This "defect" is converted into energy which is responsible for keeping the nucleus stable. This energy is called Binding Energy.
Binding energy in itself doesn't provide a good measure of stability. Rather binding energy per nucleon is a better and accepted unit. It is directly proportional to x, provided x is negative.
Lighter elements ( H1, H2, H3 ) and heavier elements( A>200) have a positive value of x, thereby making them unstable and prone to be radioactive.
Hope I have answered the question
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