Question

5
B.5. Find the equation of the line
passing through origin and parallel to
the line 3x-2y+1=0.
​

Answer 1

Step-by-step explanation:

ANSWER

Parallel lines have equal slope.

For line 3x+2y+5=0⇒2y=−3x−5⇒y=

2

−3

x−

2

5

Comparing above equation of line to the standard form of slope intercept equation y=mx+c

We have slope m=

2

−3

Thus, any line with slope m will be parallel to the given line.

Equation of such line will be y=

2

−3

x+c⇒2y=−3x+2c⇒3x+2y−2c=0 where c is any real number.

Answer 2

The given equation of line is 3x+2y+1=0

slope = 2−3

Let the required line be y=lnx+c

y=−23x+c ....(i)

Given that (i) passes through (0,1)

1=o(2−3)+c→c=1 

y=2−3x+c

y=2−3x+1

3x+2y=0