5 balls have to be placed in 12 boxes, which are divided into 3 rows of equal number of boxes. The ball must be placed in such a way that each row contains at least one ball. A box can contain only one ball. In how many ways can this be done.
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Lets say, Any 5 boxes can be chosen from 12 boxes, hence total no.= 12C5
Total ways that ball will not be placed in 1st row will be 8C5
Similarly it goes for 2nd row and 3rd row.
Total ways a row contains at least one ball will be 12C5−3(8C5) = 624.
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Answer:
ets say, total ways of placing 5 balls into 12 boxes will be 12C5
total ways that ball will not be placed in 1st row will be 8C5
Similarly it goes for 2nd row and 3rd row.
Total ways a row contains at least one ball will be 12C5−3(8C5) = 624
Step-by-step explanation:
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