Question

5 beats per second are produced on 21 is 220 then their frequencies will be​

Answer 1

Answer:

let the frequecy be = n

then the possible frequency of sonometer wire are = n + 5, n –5

n + 5 = (1/40) * sqrt (T/m),

n –5 =  (1/42) * sqrt (T/m)

Hence

n + 5/ n –5 = 21/ 20

20 n + 100 = 21 n – 105

n = 205 Hz