Question

5 binary compounds from hydroxide (oh-)? anyone answer i will make him brainliest

Answer 1

    

 

Binary Compounds All true binary

·        Putting it all together we have K2S.

 

Write the formula for magnesium chloride.

·        The chemical symbol of magnesium is Mg. Mg is in the 2nd column of the periodic table, therefore, its oxidation state is +2.

·        Chloride is derived from chlorine, whose symbol is Cl. Its oxidation state is -1.

                                                +2       -1

·        So far we have… Mg  Cl

·        The total positive charge must balance the total negative charge. Therefore, we need 2 chlorine atoms to give a total negative charge of -2. This balances the charge on the magnesium.

·        Putting it all together we have MgCl2. Type II Binary Compounds
For Type II binary compounds the metal present is NOT found in either Group 1 or Group 2 on the periodic table. The naming system for this type of compound is found below.
Rules for naming Type II binary compounds
1.         The cation is always named first and the anion second.
2.         A simple cation (obtained from a single atom) takes its name from the name of the element. Include a Roman numeral to indicate the oxidation number (charge) on the metal cation.
3.         A simple anion (obtained from a single atom) is named by taking the first part of the element name (the root) and adding the letters “IDE.”

 

Name the compound FeCl2.

·        Fe is the chemical symbol for iron.

o       Fe is not in the 1st or 2nd column; therefore a Roman numeral is needed in the name. We’ll come back to that shortly.

·        Cl is the chemical symbol for chlorine, whose root is “chlor.” Add the “ide” ending to get chloride.

·        At this point we have iron (??) chloride.

·        To find the Roman numeral…

o       Find the charge of the anion.

§         Cl has a -1 charge.

o       Multiply times the number of those atoms to get the total negative charge.

§         There are 2 Cl atoms.

§         2 times -1 = -2. <--- total negative charge.

o       Balance total negative charge with total positive charge.

§         The total negative charge of -2 must bebalanced with a total positive charge of +2.

o       Divide the total positive charge by the number of atoms to get Roman numeral.

§         There is only 1 Fe

§         +2 divided by 1 = +2. The Roman numeral is II.

·        Put the pieces together to get the name iron (II) chloride.

 

Name the compound PbS2.

·        Pb is the chemical symbol for lead.

o       Pb is not in the 1st or 2nd column; therefore a Roman numeral is needed.

·        S is sulfur, whose root is “sulf.” Add the “ide” ending to get sulfide.

·        At this point we have lead (??) sulfide.

·        To find the Roman numeral…

§         S has a charge of -2.

§         There are 2 sulfur atoms so…. 2 x -2 = -4. <---- total negative charge

§         The total positive charge must be +4.

§         There is 1 lead atom so… +4 ÷ 1 = +4. The Roman numeral is IV.

·        Put the pieces together to get the name lead (IV) sulfide.

 

Write the formula for nickel (III) oxide.

·        The chemical symbol of nickel is Ni. The oxidation state is +3, as given by the Roman numeral.

·        Oxide is derived from oxygen, whose symbol is O. Its oxidation state is -2.

                                           +3   -2

·        So far we have Ni O.

·        In order to balance the charges we find the least common multiple (LCM) of 3 and 2. The LCM is 6. We need two Ni atoms (+6 ÷ +3 = 2) and three O atoms (-6 ÷ -2 = 3) to balance the charges.

·        Putting it all together we have Ni2O3.

 

Write the formula for lead (IV) nitride.

·        The chemical symbol of lead is Pb. The oxidation state is +4.

·        Nitride is derived from nitrogen, whose symbol is N. Its oxidation state is -3.

                                           +4   -3

·        So far we have Pb N.

·        The LCM of 4 and 3 is 12. We need three Pb atoms (+12 ÷ +4 = 3) and 4 N atoms    (-12 ÷ -3 = 4) to balance the charges.

·        Putting it all together we have Pb3N4.

 

Write the name for iron (II) oxide.

·        The chemical symbol of iron is Fe. The oxidation state is +2.

·        Oxide is derived from oxygen, whose symbol is O. Its oxidation state is -2.

                                           +2      -2

·        So far we have Fe   O

·        Since the charges already balance there is no additional work to be done.

·        Putting it all together we have FeO.

 

Answer 2

NH4 + ammonium CO3 2– carbonate H3O + hydronium HCO3 – hydrogen carbonate (bicarbonate) OH– hydroxide OCN – cyanate CN– cyanide SCN– thiocyanate O2 2- peroxide S2O3 2– thiosulfate N3 - azide CrO4 2– chromate NO2 – nitrite Cr2O7 2– dichromate NO3 – nitrate SO4 2– sulfate ClO– hypochlorite SO3 2– sulfite ClO2 – chlorite HSO4 – hydrogen sulfate (bisulfate) ClO3 – chlorate PO4 3– phosphate ClO4 – perchlorate HPO4 2– monohydrogen phosphate MnO4 – permanganate H2PO4 – dihydrogen phosphate C2H3O2 – acetate (OAc- ) HSO3 – hydrogen sulfite (bisulfite)