Math, asked by johnkoshypanicker66, 6 months ago

5 black and 5 white beads in one box. 6 black and 4 white in another. one has to choose a box and pick a bead. if it is black he wins which box is better choice

Answers

Answered by vikash585826
0

Answer:

Good morning bhai happy 3rd day of navratri

Answered by Anonymous
2

Step-by-step explanation:

The probability of getting black ball in box no.1 is 0.5

probabilty \:of \: getting  \: black\:  \: b  all  \: in \: box \: no.1</strong><strong>=</strong><strong> \frac{5}{10}  =  \frac{1}{2}  = 0.5

Now the probability of getting black in box no.2 0.6

probability \: of \: getting \: black \: ball \: in \: box \: no.2 =  \frac{6}{10}  = 0.6

  • Box no.1=0.5
  • Box no.2=0.6

Hence there is more probability of getting black ball in box no.2 instead of box no.1

So box which contains 6 black balls gives better choice.

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