Math, asked by souravdey8984, 1 year ago

5 boys and 4 girls are ti be seated in a row ssuch dat all girls are together. how many such arrangements r possible?

Answers

Answered by sagarkes
0
5 such arrangement are possible
Answered by Anonymous
110

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5 boys and 4 girls are to be seated in a row so that the girl gets the even places.

The 5 boys can be seated in 5! Ways.

For each of the arrangement, the 4 girls can be seated only at the places which are cross marked to make girls occupy the even places).

B x B x B x B x B

So, the girls can be seated in 4! Ways.

Hence, the possible number of arrangements = 4! × 5! = 24 × 120 = 2880

Hope it's Helpful.....:)

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