Question

5 boys and 4 girls are to be seated in a row such that no two girls sit together how many such arrangements are possible​

Answer 1

Answer:

Boy      Girl      Boy      Girl       Boy      Girl       Boy      Girl      Boy

Answer 2

${ \huge{\boxed{\tt {\color{red}{answer}}}}}$

5 boys and 4 girls are to be seated in a row so that the girl gets the even places.

The 5 boys can be seated in 5! Ways.

For each of the arrangement, the 4 girls can be seated only at the places which are cross marked to make girls occupy the even places).

B x B x B x B x B

So, the girls can be seated in 4! Ways.

Hence, the possible number of arrangements = 4! × 5! = 24 × 120 = 2880

Hope it's Helpful.....:)