5 boys and 4 girls are to be seated in a row such that no two girls sit together how many such arrangements are possible
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Boy Girl Boy Girl Boy Girl Boy Girl Boy
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5 boys and 4 girls are to be seated in a row so that the girl gets the even places.
The 5 boys can be seated in 5! Ways.
For each of the arrangement, the 4 girls can be seated only at the places which are cross marked to make girls occupy the even places).
B x B x B x B x B
So, the girls can be seated in 4! Ways.
Hence, the possible number of arrangements = 4! × 5! = 24 × 120 = 2880
Hope it's Helpful.....:)
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