Question

5 boys and 5 girls sit in a row at random. the probability that boys and girls sit alterntively is

Answer 1

they can be less or they can be more

Answer 2

There are 5 boys and 5 girls n(S) = 10!.

Out of the probability that both girls and boys sit alternatively n(E) = 2 * 5! * 5!


P(E) = n(E)/n(S)

       = 2 * 5! * 5!/10!