5 bulbs each rated 1000watts are used for 4 hours, heater rated 1500 watts used for 2 hours an electric iron rated 1000watts is used for 5 hours.calculate the total energy consumed by them in terms of the commercial unit of energy
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total power of appliance in the house=(1000+1500+1000)watts=3500watt in kw 3.5 kw
total time = (4+2+5)=11 hours in second= 11×60×60= 39600s
total energy consumed=3.5×39600=139660j or 139.66kj
total time = (4+2+5)=11 hours in second= 11×60×60= 39600s
total energy consumed=3.5×39600=139660j or 139.66kj
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