-5 by 11 to get 5 by 9
i need ans for this .
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Answer:
the answer is 100/99 because if you subtract 5/11 from 100/99 it will give 5/9.
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a2+b2=1012, there must exist k,r,s∈N, r>s, gcd(r,s)=1, r, s of opposite parity, such that 101=k(r2+s2). Since r2+s2>1 and 101 is prime, it follows that k=1 and r2+s2=101. Fermat's theorem together with the observation 101=102+12 implies {r,s}={1,10}. Thus, {a,b}={102–12,2⋅10⋅1}={20,99}.
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