5 by 7 of a number exceeded by 65 gives 80 find the number
Answers
Answered by
25
5/7×x+65=80
5/7x=80-65
5/7x=15
x=15×7/5
x=21
5/7x=80-65
5/7x=15
x=15×7/5
x=21
Answered by
14
Let the number be x
ATQ:
5x/7+65=80
(5x+455)=80×7
5x+455=560
5x=560-455
5x=105
x=105/5
x=21
ATQ:
5x/7+65=80
(5x+455)=80×7
5x+455=560
5x=560-455
5x=105
x=105/5
x=21
satyam294:
bhar answer is wrong
Similar questions