Question

5. Calculate no. of moles in a) 44.8 L H, at STP. b)9gm H20.​

Answer 1

←: Answer :→

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1) 44.8 L of H at STP

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$\bold {\green { Moles = \dfrac{Given \; Volume}{22.4} }}$

$\bold {\pink { Moles = \dfrac{44.8}{22.4} }}$

$\boxed { \bold {\orange { :\leadsto Moles \; of \; H = 2 \; moles }} }$

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2) 9 gm of H₂O

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$\bold {\green { Moles = \dfrac{Given \; Mass}{Molar \; Mass} }}$

$\bold {\pink { Moles = \dfrac{9}{18} }}$

$\boxed { \bold {\orange { :\leadsto Moles \; of \; H_2O = 0.5 \; moles }} }$

Answer 2

Answer:

a)2 b)0.5

Explanation:

a) 44.8L H at stp

as we know at all gases occupy 22.4L at stp

and 22.4L of H gas ------> 1 mole of H gas

so 44.8L of H gas -------> x moles of H gas

x= 44.8/22.4

x=2 moles of H gas.

b)9gm H20

gram molecular weight of h2o is 18g

given weight= 9g

no of moles formula= given weight/ gram molecular weight.

no of moles= 9/18

no of moles= 0.5 moles.

hope it's helpful!