5: Calculate the angular speed of rotation of the Earth so that the apparent g at the equator becomes
zero. Also calculate the length of the day in this situation.
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3
Answer:
For apparent g at equator to be 0,
mω
2
R−mg=0
ω=
R
g
=
6400000
9.8
=1.24X10
−3
rad/s
Also, length of day is equal to the time of one rotation.
Hence, T=
ω
2π
=
1.24X10
−3
2π
=5067.74s=1.41hr
Answer is 1.41hr.
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