Question

5. Calculate the compound interest for the second year on 6000 invested for 3 years at
10% p.a. Also find the sum due at the end of third
year.​

Answer 1

Answer:

compound Interest=p(1+R/100)^n

6000(1+10/100)^1

6000×11/10

600×11=6600

6600 for second year

At the end of third year

6000(11/10)^3

6×1331=7986

sum due=7986-6600=1386

PLEASE MARK ME AS BRAINLIEST AND FOLLOW ME