Question

5. Calculate the magnitude of force required in newton to produce a pressure of 28500 Pa on an area
of 100 cm?
6. (a) A boy weighs 50 N. The area of contact of his two feet is 10 cm2. What pressure does he exert
on the ground if he stands on one foot?
Friends please help
I have very important assignment
After 30 mins please help
Person who does not know the answers please don't reply ​

Answer 1

Answer:

5. p=28500pa,

a=100cm=1metre( because we change unit into so unit)

formula of p=f/a

so, f=p*a

28500*1= 28500N

6. p =f/a

p= 50/10

p=5 pa

Answer 2

Given :-

1. A pressure of 28500 Pa on an area of 100 cm²
2. A boy weighs 50 N. The area of contact of his two feet is 10 cm2.

To find :-

1. Magnitude of force required in Newton
2. Pressure does boy exert on the ground if he stands on one foot

Solution :-

✩According to the first question✩

• Pressure produced = 28500Pa

• Area where pressure exerted = 100cm²

✶ S.I unit of area is m². So, convert cm² to m² by dividing 10000 ✶

→ 1m² = 10000cm² ←

→ Area = 100/10000

→ Area = 0.01m²

Now, as we know that

→ Pressure = Force/Area

→ Force = Pressure × Area

✩ Put the values of pressure and area ✩

→ Force = 28500/0.01

→ Force = 2850000 N

Hence,

• Magnitude of force is 2850000 N

✩ Now, according to 2nd question ✩

• Force = 50 N

• Area of contact of his two feet = 10 cm²

✩Convert cm² to m² by dividing 10000

→ Area = 10cm²

→ Area = 0.001

So,

→ Pressure = Force/Area

✶ Put the values of force and area ✶

→ Pressure = 50/0.001

→ Pressure = 50000 N

Hence,

• Pressure does boy exert on the ground is 50000N