Question

5. Calculate the minimum voltage to cause the
electrolysis of a solution of copper nitrate under
standard conditions. Give that E Cu2+/Cu = 0.34 V
and EºH2O/H+= - 1.23 V.​

Answer 1

Given that,

The  electrolysis of a solution of copper nitrate under  standard conditions.

$E_{Cu^{+}/Cu}=0.34\ V$

$E^{0}_{H_{2}O/H^{+}}=-1.23\ V$

We know that,

The minimum voltage is equal to the cathode voltage subtract anode voltage.

In mathematically,

$E=E_{cathode}-E_{anode}$

We need to calculate the minimum voltage

Using formula of voltage

$E=E_{cathode}-E_{anode}$

Put the value into the formula

$E=0.34-(-1.23)$

$E=1.57\ V$

Hence, The minimum voltage is 1.57 V.