Question

5.
Calculate the molarity of 49% (w/w) aqueous solution
of H2SO4 if density of solution is 0.1 g/cm3​

Answer 1

Answer:

Search...

gabbargabbar074

4 weeks ago

Chemistry

Primary School

answered

5. Calculate the molarity of 49% (w/w) aqueous solution

of H,So, if density of solution is 0.1 g/cm3

1

SEE ANSWER

ADD ANSWER

+5 PTS

Log in to add comment

gabbargabbar074 is waiting for your help.

Add your answer and earn points.

Answer

0

mamtachoudhary9611

Expert

180 answers

2.4K people helped

The density of a stock solution of 49 % (ww) H2SO4 is 1.5 g/ml. The volume of this stock solution required to prepare 25 L of 0.1 MH SO, solution is (1) 33.33 ml (2) 25.55 mi (3) 43.23 mi (4) 38.25 ml than

NEET/Medical Exams

Chemistry

Solution

446

Rating

4.0 (1 ratings)

Fullscreen

Answer:- 33.4 mL volume of the stock solution for it's Solution:- Stock solution is 49% w/w. 49% ww solution as: It means 49 grams of sulfuric acid 100g(1mL1.5g) present in 100 grams of the solution. =66.7mL We want to make 2.5 L of 0.1M sulfuric acid solution from the stock are present in 66.7mL solution. We solution. let's calculate the moles need to calculate the volume of this and then grams of this diluted solution from it's given volume and 24.5 grams of sulfuric acid. molarity as: 2.5L(0.1mol1L)(98g1mol)

24.5gH2SO4(66.7mL49g)

=24.5g

=33.4mLH2SO4

So, 33.4 mL of stock solution are Density of the stock solution is 1.5 required to make 2.5L of 0.1M gram per mL. Let's calculate the sulfuric acid