Physics, asked by sag77, 10 months ago


5. Calculate the total K.E. of 1 g of nitrogen at 300 K.
* Molecule weight of nitrogen = 28. (Ans. 133.4 J)

Answers

Answered by AnmolRaii
1

Given :

mass of nitrogen :M=28

Temperature =T=77°C=77+273=350K

Gas constant R=8.31 /mol K

K.E of 1 g of Nitrogen=K.E=3RT/2M

=3x8.31x350/2x28

=155.8J

∴Kinetic energy of 1 g of nitrogen gas at 77°C is 155.8

Answered by Anonymous
0

Given :

mass of nitrogen :M=28

Temperature =T=77°C=77+273=350K

Gas constant R=8.31 /mol K

K.E of 1 g of Nitrogen=K.E=3RT/2M

=3x8.31x350/2x28

=155.8J

∴Kinetic energy of 1 g of nitrogen gas at 77°C is 155.8

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