Question

5 Cells of 1.5V each has resistance of 0.2, 0.3, 0.4, 0.5 and 1.2(ohms) respectively when connected in series. What current will they draw if they are connected through 10(ohms) resistance

Answer 1

Given

Battery=9V

resistors of 0.2 ohm, 0.3ohm, 0.4ohm, 0.5ohm and 12ohm are connected in series to battery.

R1=0.2ohm

R2=0.3ohm

R3=0.4ohm

R4=0.5ohm

R5=12ohm

As all are connected in series effective resistance would be :

Reff=R1+R2+R3+R4+R5

=0.2+0.3+0.4+0.5+12

=13.4OHMS

By ohms law : V=IR

I=V/R

=9/13.4

=0.67 A

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