5 centimetre is placed perpendicular to the principal axis of a convex lens of focal length 10 cm if the object is placed 30 cm away from the lens find the position size and nature of the image
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Answer:
15cm between 2f2 and f2
15cm between 2f2 and f2Explanation:
According to the question:
Object distance,u = -30 cm
Focal length ,f = 10 cm
Let the image distance be v
By lens formula:
1/v - 1/u = 1/f
1/v = 1/u + 1/f
1/v = 1/-30cm + 1/10cm
1/v = (-1+3)/30
1/v = 1/15 cm
V = 15cm
Thus , image is obtained at 15 cm between 2F2 and F2
Answered by
0
Explanation:
According to the question:
- Object distance,u = -30 cm
- Focal length ,f = 10 cm
Let the image distance be v
By lens formula:
- 1/v - 1/u = 1/f
- 1/v = 1/u + 1/f
- 1/v = 1/-30cm + 1/10cm
- 1/v = (-1+3)/30
- 1/v = 1/15 cm
- V = 15cm
Thus , image is obtained at 15 cm between 2F2 and F2.
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