Question

5) Check the nature of roots of quadratic equation 3x

2

- 4x – 2 = 0.​

Answer 1

Answer:

No real value

Step-by-step explanation:

3x² - 4x - 2 = 0

x = [-(-4) +/- root ( 4² - 4(3)(2)]/ 2(3)

x = [4 +/- root( 16 - 24)]/2(3)

x= [4 +/- root(-8)]/6

It has no real value

bcoz the number inside the root is negative

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Answer 2

Answer:

The roots of the equation 3x² - 4x - 2 = 0 are real and unequal.

Step-by-step explanation:

The given quadratic equation is : 3x² - 4x - 2 = 0

We need to find the nature of roots of the equation.

To find the nature of the roots we check the value of D

where D = $\sqrt{b^2-4ac}$

Therefore, here, D =  $\sqrt{(-4)^2-4*3*(-2)}$

                               =  $\sqrt{16+ 24}$

                               =  $\sqrt{40}$

Here, 3 cases exists

1. if D > 0 then the roots are real and unequal

2. if D = 0 then the roots are real and equal

3. if D < 0 then the roots are not real

Therefore, the roots of the equation 3x² - 4x - 2 = 0 are real and unequal.