Question

5.
Check whether 3 and -2 are the zeroes of the polynomial p(x) when p(x)=x^2-x-6​

Answer 1

AnsweR :-

Let's take 3 first :-

P(x) = x²- x - 6

P(3) = (3)² - (3) - 6

P(3) = 9 - 3 - 6

P(3) = 0 ans

Now let's take -2 :-

P(x) = x² - x - 6

P(-2) = (-2)² - (-2) - 6

P(-2) = 4 + 2 - 6

P(-2) = 0 ans

$\therefore$ 3 & -2 are the zeros of the above Polynomial.

Procedure :-

$\implies$ We are provided with two numbers that are 3 and -2. First we will insert 3 in place of x to see wheather it is a zero or not. And after placing it and equating it the answer we get is zero so it is.

$\implies$ In the second case we will put -2 in place of x then we will equate the whole expression again. That -2 will be one +4 because because when we multiply any negetive number with itself 2 times it will become positive. After equating it we again get the zero so it is too.

Just like this 3 and -2 are the zeros of the Polynomial.

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