5 Check whether 6" can end with the digit 0 for any natural number n. .
6. Explain why 7 x 1113+13 and 7x 6 x 5 x 4 x 3 x 2 x 1 + 5 are composite number
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Step-by-step explanation:
1)6n=2n×3n
Here the factors 5 and 2 are not divisible by 0
So 6n cannot end with 0
2)7×6×5×4×2×1+5
5(7×6×4×2+1)
=5×337
Here 5 and 337 are composite no
As it has 2 factors
Please mark it as brainliest answer
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