5. Check whether 6" can end with the digit O for any natural number n.
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. It can be observed that 5 is not in the prime factorisation of 6n. Hence, for any value of n, 6n will not be divisible by 5. Therefore, 6n cannot end with the digit 0 for any natural number n.
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the power of any number is a multiple of itself
let us give the values of n
6,6×6,6×6×6.... 6 = 2 × 3
6 contains only two factors 2 and 3
but a digit to end with zero we require 5 as a factor
hence 6 to the power of n cannot end with the digit 0 for any natural number n
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