Question

5. Check whether 8 can end with the digit 0 for any natural number n.​

Answer 1

Explanation:

ANSWER :

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Hey!__________Hey!_______________Let us think of some numbers which end the digit 0

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5Many more...

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5Many more...Now, Clearly we can see that numbers ending with 0 has prime factors as 2 and 5, take any number ending with digit 0 , it will do have 2 and 5 as a factor.

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5Many more...Now, Clearly we can see that numbers ending with 0 has prime factors as 2 and 5, take any number ending with digit 0 , it will do have 2 and 5 as a factor.But,

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5Many more...Now, Clearly we can see that numbers ending with 0 has prime factors as 2 and 5, take any number ending with digit 0 , it will do have 2 and 5 as a factor.But,8^n = (4 × 2) ^n

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5Many more...Now, Clearly we can see that numbers ending with 0 has prime factors as 2 and 5, take any number ending with digit 0 , it will do have 2 and 5 as a factor.But,8^n = (4 × 2) ^nIt doesn't have 5 as it's factor thus 8^n cannot end with zero for any natural number n.

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5Many more...Now, Clearly we can see that numbers ending with 0 has prime factors as 2 and 5, take any number ending with digit 0 , it will do have 2 and 5 as a factor.But,8^n = (4 × 2) ^nIt doesn't have 5 as it's factor thus 8^n cannot end with zero for any natural number n._______________

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5Many more...Now, Clearly we can see that numbers ending with 0 has prime factors as 2 and 5, take any number ending with digit 0 , it will do have 2 and 5 as a factor.But,8^n = (4 × 2) ^nIt doesn't have 5 as it's factor thus 8^n cannot end with zero for any natural number n._______________Hope it helps...!!!

Hey!__________Hey!_______________Let us think of some numbers which end the digit 010 = 5 × 2100 = 2 × 2 × 5 × 5Many more...Now, Clearly we can see that numbers ending with 0 has prime factors as 2 and 5, take any number ending with digit 0 , it will do have 2 and 5 as a factor.But,8^n = (4 × 2) ^nIt doesn't have 5 as it's factor thus 8^n cannot end with zero for any natural number n._______________Hope it helps...!!!Read more on Brainly.in - https://brainly.in/question/3667615#readmore