5 cm high object is placed at a distance of 10 cm from a convex lens of focal length 15 CM by drawing a ray diagram find position nature and size of image
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Answer:
h = 5 cm
u = -10 cm
f= 15 cm
v=?
h' = ?
using lens formula :
-1/u + 1/v = 1/f
- ( - 1 /10) + 1/v = 1/15
1/v = 1/15- 1/10
1/v = 2-3/30
1/v = -1/30
v = - 30
m= h'/h = v/u
m= h' /5 = -30/-10
h' = 30Ć5/10
h' = 15 cm
the image is virtual and erect
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