5 cm high object is placed at a distance of 25 cm from a converging lens of focal length of 10cm. Determine the position,size and type of the image. Solve the following example
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Answer:
given data
ho = 5 cm do = 25 cm f = 10 cm di = ? hi = ?
type of image = ?
1/f = 1/ di + 1/d0
1/f - 1/do = 1/di = 1/10 - 1/25 = 0.1 - 0.04 =0.06 cm
di = 1/0.06= 16.6 cm
for hi
M = - di/ do = - 16.6cm / 25 cm= - 0.664
also
M = hi/ho
- 0.664 * ho = hi = - 0.664 * 5 cm = - 3.32 cm
the image is real and inverted , located opposite side of the lens
Explanation:
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