Question

- 5 cm high object is placed at a
distance of 25 cm from a converging
lens of focal length of 10 cm.
Determine the position, size and type
of the image.
n
​

Answer 1

Answer:

the height of object = 5cm

position of object,u = 25 cm

focol length of the lens f = 10 cm

the position of image,v = ?

size of the image

nature of image

we know that,

1/v - 1/u = 1/f

1/v + 1/25 = 1/10

1/v= 1/10 -1 /25

1/v = (5-2)/50

hence, 1/v = 3/50

so v= 50/3 = 16.66 cm

no we know that

therefore the distance of the image is

16.66 cm on the opposite side of the lens

magnification = v/u

hence m= 16.66 /-25 = -0.66

we know that

m= hight of image/height of object

or, -0.66 = height of image/5 cm

hence height of image = -3.3cm

position of image = 16.66 cm

size of image = -3.3cm

nature of image = real and inverted