5. Consider an equilateral triangle ABC as given in the following diagram: D A С B Two people start at the same time from points A and B with speeds 30 km per hour and 20 km per hour respectively, and move on the sides of the triangle in the clockwise direction. They meet each other for the first time at (a) point C (b) a point between C and A (c) a point between A and B (d) point A
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One option is that all the three particles will meet at centroid and value of centroid is a, of an equilateral triangle.
The velocity of particle A will be divided into two components i.e. vcos60 and vsin60.
V=v+v cos
60V=v+v/2V=3v/2
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Time=tS =Distance traveled by A= that by B= that by C centroid-aV=s/tt-s/vt=a=3v/2t= 2a/ 3v
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