Question

5)Construct the parallelogram ABCD such that l(BC) = 6.3 cm, m Angle ABC=45 and 1(AB)=4 cm.​

Answer 1

⇒ Draw a line segment AB = 6cm.

⇒ Construct an angle of 60° at point B.

⇒ Cut off BC = 4cm.

⇒ We know that adjacent angles of parallelogram are supplementary then, construct an angle of 120°

at point A and C which meet at point D.

⇒ Thus, ABCD is a required parallelogram.

⇒ Let AB=a=6cm and BC=b=4cm --- ( 1 )

⇒ Perimeter of parallelogram ABCD=2(a+b)

⇒ 2(6+4) [From( 1 )]

∴ Perimeter of parallelogram ABCD=20cm.